if leangth of rectangle park is 22m and its area is 286m² find its width and perimeter About the author Lydia
Answer :- Given :- Length of park = 22 m Area = 286 m² To Find :- Width Perimeter Solution :- We know that, → Area = Length × Width Substituting the values of area and length in formula :- → 286 = 22 × w → w = 286 / 22 → w = 13 Width of park = 13 m Calculating Perimeter :- We know that, → Perimeter = 2 ( Length + Width ) Substituting the values in formula :- → Perimeter = 2 ( 22 + 13 ) → Perimeter = 2 ( 35 ) → Perimeter = 70 Perimeter of park = 70 m Reply
Answer: Given:– If length of rectangle park is 22m and its area is 286m². Find its width and perimeter. To Find:– The width and perimeter. Note:– ●》Area = length × width when it is transposed, Width = [tex] \frac{Area}{Length} [/tex]. ●》After finding width, Perimeter of rectangle park = 2 × ( Length + width ). Solution:– [ First, Width ] [tex] \huge\red{Length = 22m, its \ \ Area = 286m², Width = ?} [/tex] ☆ According to note first point~ ▪︎[tex] Width = \frac{Area}{Length} [/tex] ▪︎[tex] Width = \frac{286m²}{22m} [/tex] ☆ After dividing and square will be canceled from metre~ ▪︎[tex] Width = 13m [/tex] [tex] \huge\pink{Width = 13m} [/tex] _______________________________ [ Now, Perimeter ] [tex] \huge\red{Length = 22m, Width = 13m} [/tex] ☆ According to note second point~ ▪︎[tex] Perimeter \ \ of \ \ rectangle \ \ park = 2 × ( Length + Width ) [/tex] ▪︎[tex] Perimeter \ \ of \ \ rectangle \ \ park = 2 × ( 22m + 13m ) [/tex] ▪︎[tex] Perimeter \ \ of \ \ rectangle \ \ park = 2 × 35m [/tex] ☆ After multiplying~ ▪︎[tex] Perimeter \ \ of \ \ rectangle \ \ park = 70m [/tex] [tex] \huge\pink{Perimeter \ \ of \ \ rectangle \ \ park = 70m} [/tex] Answer:– Hence, Width = 13m Perimeter of rectangle park = 70m. :) Reply
Answer :-
Given :-
To Find :-
Solution :-
We know that,
→ Area = Length × Width
Substituting the values of area and length in formula :-
→ 286 = 22 × w
→ w = 286 / 22
→ w = 13
Width of park = 13 m
Calculating Perimeter :-
We know that,
→ Perimeter = 2 ( Length + Width )
Substituting the values in formula :-
→ Perimeter = 2 ( 22 + 13 )
→ Perimeter = 2 ( 35 )
→ Perimeter = 70
Perimeter of park = 70 m
Answer:
Given:–
If length of rectangle park is 22m and its area is 286m². Find its width and perimeter.
To Find:–
The width and perimeter.
Note:–
●》Area = length × width when it is transposed, Width = [tex] \frac{Area}{Length} [/tex].
●》After finding width, Perimeter of rectangle park = 2 × ( Length + width ).
Solution:–
[ First, Width ]
[tex] \huge\red{Length = 22m, its \ \ Area = 286m², Width = ?} [/tex]
☆ According to note first point~
▪︎[tex] Width = \frac{Area}{Length} [/tex]
▪︎[tex] Width = \frac{286m²}{22m} [/tex]
☆ After dividing and square will be canceled from metre~
▪︎[tex] Width = 13m [/tex]
[tex] \huge\pink{Width = 13m} [/tex]
_______________________________
[ Now, Perimeter ]
[tex] \huge\red{Length = 22m, Width = 13m} [/tex]
☆ According to note second point~
▪︎[tex] Perimeter \ \ of \ \ rectangle \ \ park = 2 × ( Length + Width ) [/tex]
▪︎[tex] Perimeter \ \ of \ \ rectangle \ \ park = 2 × ( 22m + 13m ) [/tex]
▪︎[tex] Perimeter \ \ of \ \ rectangle \ \ park = 2 × 35m [/tex]
☆ After multiplying~
▪︎[tex] Perimeter \ \ of \ \ rectangle \ \ park = 70m [/tex]
[tex] \huge\pink{Perimeter \ \ of \ \ rectangle \ \ park = 70m} [/tex]
Answer:–
Hence,
:)