If + is -, ×is÷, – is x and ÷is +, then the correct
value of A is
A = 3 – 4 + 6 x 2 = 7
(1) 20
(2) 14
(3)

If + is -, ×is÷, – is x and ÷is +, then the correct
value of A is
A = 3 – 4 + 6 x 2 = 7
(1) 20
(2) 14
(3) 2
(4) 16
with full explanation​

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Alice

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