Answer: here given cosθ+secθ=4…(i) Step-by-step explanation: on squaring eqn. i both side, we get cos²θ+sec²θ+2×cosθ×secθ=16 =>cos²θ+sec²θ+2=16 =>cos²θ+sec²θ=14. plz mark me as brainliest.. Reply
Step-by-step explanation: [tex] \cos \alpha + \sec\alpha = 4 \\ { \cos }^{2} \alpha + { \sec }^{2} \alpha = 16[/tex] Reply
Answer:
here given cosθ+secθ=4…(i)
Step-by-step explanation:
on squaring eqn. i both side, we get
cos²θ+sec²θ+2×cosθ×secθ=16
=>cos²θ+sec²θ+2=16
=>cos²θ+sec²θ=14.
plz mark me as brainliest..
Step-by-step explanation:
[tex] \cos \alpha + \sec\alpha = 4 \\ { \cos }^{2} \alpha + { \sec }^{2} \alpha = 16[/tex]