if area of rombus is 100cm2 and one of its diagnol is twice of other them find the value of bigger diagonal​

2 thoughts on “if area of rombus is 100cm2 and one of its diagnol is twice of other them find the value of bigger diagonal​”

1. Answer:

   20cm

   Step by step explanation:

   Given,

   Area of rhombus = 100cm^2 and one diagonal is twice the other.

   Now,

   Let one diagonal be Y and the other diagonal be 2Y

   Area of rhombus = 1/2 x length of Diagonal 1 × length of diagonal 2

   substituting the values in the above formula,

   100 = 1/2 x Y x 2Y

   100 = 1/2 x 2Y^2

   100 = Y^2 (2 and 2 cancels out in the previous step)

   root100 = Y

   10cm = Y

   Therefore the first diagonal will be = Y = 10cm

   And second diagonal will be = 2Y = 2×10 = 20cm

   So the length of bigger diagonal is 20cm.

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2. Answer:

   • The value of bigger diagonal is 20 cm.

   Step-by-step explanation:

   Given that:

   • Area of a rhombus is 100 cm².
   • One of its diagnol is twice of other.

   To Find:

   • The value of bigger diagonal.

   Let us assume:

   • Smaller diagonal of a rhombus be x.
   • Bigger diagonal = 2x

   Formula used:

   • Area of a rhombus = (P × Q)/2

   Where,

   • P = Bigger diagonal of a rhombus
   • Q = Smaller diagonal of a rhombus

   Finding the value of bigger diagonal:

   According to the question.

   ⟶ (P × Q)/2 = 100

   ⟶ (2x × x)/2 = 100

   ⟶ 2x²/2 = 100

   ⟶ x² = 100

   ⟶ x = √100

   ⟶ x = 10

   ∴ The value of bigger diagonal = 2x = (2 × 10) = 20 cm

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