If Alpha, Beta Are Zeroes of x^2+5x+5, Find A Polynomial With Zeroes 1/Alpha And 1/Beta About the author Audrey
Step-by-step explanation: Given:– x^2+5x+5 To find:– If α and β are the zeroes of x^2+5x+5 then Find a Polynomial with zeroes 1/α and 1/β? Solution :– Given quardratic polynomial is x^2+5x+5 On Comparing this with the standard quadratic Polynomial ax^2+bx+c a = 1 b= 5 c= 5 We know that Sum of the zeroes = -b/a => α + β = -5/1 α + β = -5 ——-(1) Product of the zeroes = c/a α β = 5/1 α β = 5———(2) We know that The Quadratic Polynomial whose zeroes (1/α) and (1/β) is K[x^2-[(1/α)+(1/β)]x+(1/α)(1/β)] => K[x^2-{(α + β)/α β}x +(1/α β)] =>K[x^2-(-5/5)x+(1/5)] =>K[x^2-(-1)x+(1/5)] =>K[x^2+x+(1/5)] => K[5x^2+5x+1]/5 If K = 5 then => 5[5x^2+5x+1]/5 =>5^2+5x+1 Answer:– The required quardratic polynomial is 5^2+5x+1 Used formulae:– The standard quadratic Polynomial ax^2+bx+c Sum of the zeroes = -b/a Product of the zeroes = c/a The Quadratic Polynomial whose zeroes α and β is K[x^2-(α+β)x+αβ] Reply
Step-by-step explanation:
Given:–
x^2+5x+5
To find:–
If α and β are the zeroes of x^2+5x+5 then Find a Polynomial with zeroes 1/α and 1/β?
Solution :–
Given quardratic polynomial is x^2+5x+5
On Comparing this with the standard quadratic Polynomial ax^2+bx+c
a = 1
b= 5
c= 5
We know that
Sum of the zeroes = -b/a
=> α + β = -5/1
α + β = -5 ——-(1)
Product of the zeroes = c/a
α β = 5/1
α β = 5———(2)
We know that
The Quadratic Polynomial whose zeroes (1/α) and (1/β) is K[x^2-[(1/α)+(1/β)]x+(1/α)(1/β)]
=> K[x^2-{(α + β)/α β}x +(1/α β)]
=>K[x^2-(-5/5)x+(1/5)]
=>K[x^2-(-1)x+(1/5)]
=>K[x^2+x+(1/5)]
=> K[5x^2+5x+1]/5
If K = 5 then
=> 5[5x^2+5x+1]/5
=>5^2+5x+1
Answer:–
The required quardratic polynomial is 5^2+5x+1
Used formulae:–