If alpha and beta are the zeros of polynomial 3 x^2-5x-9 find value of 2/ Alpha + 2/ beta.. Please solve this question fast, don’t

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1. Answer:

   [tex] \frac{ – 10}{9} [/tex]

   Step-by-step explanation:

   By cross multiplying, we get

   [tex] \frac{2}{ \alpha } + \frac{2}{ \beta } = \frac{2( \alpha + \beta) }{ \alpha \beta } [/tex]

   Now, alpha and beta are zeros of quadratic x^2-5x-9

   so using the property for sum of roots and product of roots of a quadratic polynomial, we get

   [tex] \alpha + \beta = \frac{ – ( – 5)}{1} = 5[/tex]

   [tex] \alpha \beta = \frac{ – 9}{1} = – 9[/tex]

   So,

   [tex] \frac{2}{ \alpha } + \frac{2}{ \beta } = \frac{2( \alpha + \beta) }{ \alpha \beta } = \frac{2 \times 5}{ – 9} = \frac{ – 10}{9} [/tex]

   So answer is (-10/9)

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