If a2-3a+1=0 and a is not equal to 0. Find a+I upon a
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2 thoughts on “If a2-3a+1=0 and a is not equal to 0. Find a+I upon a <br /> ​”

1. Answer:

   3

   Step-by-step explanation:

   ⇒ a² – 3a + 1 = 0

   ⇒ a² + 1 = 3a

   Divide both sides by a:

   ⇒ (a² + 1)/a = 3a

   ⇒ (a²/a) + (1/a) = 3a/a

   ⇒ a + (1/a) = 3

   Hence, the value of a + 1/a is 3

   Method 2: if you’re familiar with roots. Let the roots be x and y.

   Product of roots = xy = 1 ⇒ y = 1/x

   Sum of roots = x + y = – (-3) = 3

   Thus,

   ⇒ x + y = 3 ⇒ x + 1/x = 3

   Replacing x with a(as x represents a):

   ⇒ a + 1/a = 3 required value

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2. a²-3a+1 = 0 αnd α is not equal to 0

   • a²+ 1 = 3a
   • a² + 1 / a = 3 a
   • a²/a + 1 / a = 3 a/a
   • a + 1 / a = 3

   So, a+1/a = 3

   a+1/a = 3

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   hope it helps

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