Answer: □ ABCD is a parallelogram consider Δ ACD and Δ ABD AC = BD …. (given) AB = DC …. (opposite sides of parallelogram) AD = AD …. (common side) ∴Δ ACD ≅Δ ABD (sss test of congruence) ∠ BAD = ∠ CDA …. (cpct) ∠BAD+∠CDA=180 ∘ . [Adjacent angles of parallelogram are supplementary] so ∠ BAD and ∠ CDA are right angles as they are congruent and supplementary. Therefor, □ ABCD is a rectangle since a parallelogram with one right interior angle is a rectangle. Reply
Answer:
□ ABCD is a parallelogram
consider Δ ACD and Δ ABD
AC = BD …. (given)
AB = DC …. (opposite sides of parallelogram)
AD = AD …. (common side)
∴Δ ACD ≅Δ ABD (sss test of congruence)
∠ BAD = ∠ CDA …. (cpct)
∠BAD+∠CDA=180
∘
. [Adjacent angles of parallelogram are supplementary]
so ∠ BAD and ∠ CDA are right angles as they are congruent and supplementary.
Therefor, □ ABCD is a rectangle since a
parallelogram with one right interior angle is a rectangle.