If a and B are the zeroes of the quadratic polynomial f(x) = 6x^2+ x – 2, then the value of 1.a^2+b^2. 2.1/a+1/b About the author Kennedy
Step-by-step explanation: f(x)=6x 2 +x−2 a,b are its zero’s / roots. a+b= 6 −1 ,ab= 6 −2 =−1/3 b a + a b = ab a 2 +b 2 = ab (a+b) 2 −2ab = (−1/3) (−1/6) 2 −2(−1/3) = −1/3 36 1 + 3 2 =−( 12 1 +2)= 12 −25 Reply
Answer:
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Step-by-step explanation:
f(x)=6x
2
+x−2
a,b are its zero’s / roots.
a+b=
6
−1
,ab=
6
−2
=−1/3
b
a
+
a
b
=
ab
a
2
+b
2
=
ab
(a+b)
2
−2ab
=
(−1/3)
(−1/6)
2
−2(−1/3)
=
−1/3
36
1
+
3
2
=−(
12
1
+2)=
12
−25