if x-4 is a factor of x³-3x² a+2 a+2a²x+b then the valve of b is​

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1. Given : If x – a is a factor of x³ – 3x²a + 2a²x + b .

   Let f (x) = x³ – 3x²a + 2a²x + b

   Since, x – a is a factor of f(x) then, f (a) = 0

   ⇒ a³ – 3a²a + 2a²a + b = 0

   ⇒ a³ – 3a³ + 2a³ + b = 0

   ⇒ – 2a³ + 2a³ + b = 0

   ⇒ b = 0

   Hence, the value of b is 0.

   Among the given options option (A) 0 is correct.

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