If 3 chairs and 1 table costs Rs. 1500 and 6 chairs and 1 table costs Rs.2400. Form linear equations to represent this situation. About the author Luna
Answer: mark me as BRAINLIST and thanks my answer Step-by-step explanation: Let the cost of 1 chair be Rs x and the cost of 1 table be Rs y. So, 3x + y = 1500…(1) And 6x + y = 2400…(2) Equations (1) and (2) represent the situation described in the question. From (1) and (2) 3x = 900 So, x = 300 So, y = 600 So, the cost of 1 chair is Rs 300 And the cost of 1 table is Rs 600 Reply
Answer: let’s the chair cost price be x and table be y from 1st condition, 3x + y = 1500 —–(1) 6x + y = 2400 —–(2) subtract the equations 1st and 2nd 6x + y = 2400 – 3x – y = -1500 ___________ 3x = 900 x = 300 —–(3) put the value in equations 1st 6 × 300 + y = 2400 1800 + y = 2400 y = 2400 – 1800 y = 600 therefore, cost price of a chair is rs 300 and table is rs.600. Reply
Answer:
mark me as BRAINLIST and thanks my answer
Step-by-step explanation:
Let the cost of 1 chair be Rs x and the cost of 1 table be Rs y.
So, 3x + y = 1500…(1)
And 6x + y = 2400…(2)
Equations (1) and (2) represent the situation described in the question.
From (1) and (2)
3x = 900
So, x = 300
So, y = 600
So, the cost of 1 chair is Rs 300
And the cost of 1 table is Rs 600
Answer:
let’s the chair cost price be x and table be y
from 1st condition,
3x + y = 1500 —–(1)
6x + y = 2400 —–(2)
subtract the equations 1st and 2nd
6x + y = 2400
– 3x – y = -1500
___________
3x = 900
x = 300 —–(3)
put the value in equations 1st
6 × 300 + y = 2400
1800 + y = 2400
y = 2400 – 1800
y = 600
therefore, cost price of a chair is rs 300 and table is rs.600.