If (x,3),(6,3),(8,2) and (9,4) are the vertices of a parallellogram taken in order ,then find the value of x and y.​

If (x,3),(6,3),(8,2) and (9,4) are the vertices of a parallellogram taken in order ,then find the value of x and y.​

About the author
Parker

1 thought on “If (x,3),(6,3),(8,2) and (9,4) are the vertices of a parallellogram taken in order ,then find the value of x and y.​”

  1. Answer:

    Let A be the (x, 3), B be the (6,3), C be the (8,2) and D be the (9,4)

    A = (x1,y1) = (x, 3)

    B = (x2,y2) = (6,3)

    C = (x3,y3) = (8,2)

    D = (x4,y4) = (9,4)

    It is given that ABCD is a parallelogram.

    Diagonals of the parallelogram bisect each other.

    Mid-point of AC = Mid-point of BD

    Mid-point of AC = x1 + x3/2 , y1 + y3/2

    = x + 8/2 , 3 + 2/2

    = x + 8/2 , 5/2

    Mid-point of BD = x2 + x4/2 , y2 + y4/2

    = 6 + 9 /2 , 3 + 4/2

    = 15/2 , 7/2

    x + 8/2 = 15/2

    x + 8 = 15

    x = 15- 8

    x = 7

    Reply

Leave a Comment