If (x,3),(6,3),(8,2) and (9,4) are the vertices of a parallellogram taken in order ,then find the value of x and y. About the author Parker
Answer: Let A be the (x, 3), B be the (6,3), C be the (8,2) and D be the (9,4) A = (x1,y1) = (x, 3) B = (x2,y2) = (6,3) C = (x3,y3) = (8,2) D = (x4,y4) = (9,4) It is given that ABCD is a parallelogram. Diagonals of the parallelogram bisect each other. Mid-point of AC = Mid-point of BD Mid-point of AC = x1 + x3/2 , y1 + y3/2 = x + 8/2 , 3 + 2/2 = x + 8/2 , 5/2 Mid-point of BD = x2 + x4/2 , y2 + y4/2 = 6 + 9 /2 , 3 + 4/2 = 15/2 , 7/2 x + 8/2 = 15/2 x + 8 = 15 x = 15- 8 x = 7 Reply
Answer:
Let A be the (x, 3), B be the (6,3), C be the (8,2) and D be the (9,4)
A = (x1,y1) = (x, 3)
B = (x2,y2) = (6,3)
C = (x3,y3) = (8,2)
D = (x4,y4) = (9,4)
It is given that ABCD is a parallelogram.
Diagonals of the parallelogram bisect each other.
Mid-point of AC = Mid-point of BD
Mid-point of AC = x1 + x3/2 , y1 + y3/2
= x + 8/2 , 3 + 2/2
= x + 8/2 , 5/2
Mid-point of BD = x2 + x4/2 , y2 + y4/2
= 6 + 9 /2 , 3 + 4/2
= 15/2 , 7/2
x + 8/2 = 15/2
x + 8 = 15
x = 15- 8
x = 7