If x^2+4y^2=40 ……………(i) and xy=6 If xy=6 Therefore, x=6/y Put x=6/y in (i) (6/y)^2+4y^2=40 36/y^2+4y^2=40 (36+4y^4)/y^2=40 36+4y^4=40y^2 …………..(ii) Let y^2=z therefore, equation (ii) becomes 36+4z^2=40z ………. (iii) Divide (iii) by 4 it becomes 9+z^2=10z z^2–10z+9=0……………(iv) z^2-z-9z+9=0 z(z-1)-9(z-1)=0 (z-1)(z-9)=0 Hence, Z=1 or 9 Taking Z=1, We have y^2=1 y=1 Taking Z=9, we have y^2=9 y=3 Putting y=1 in equation (i), we have x^2+4(1)^2=40 x^2+4=40 x^2=36 x=6 Therefore, x+2y= 6+2(1)=6+2=8 Putting y=3 in equation (i) we have, x^2+4(3)^2=40 x^2+4(9)=40 x^2=40–36 x^2=4 x=2 Therefore, x+2y= 2+2(3)=2+6=8 Reply
(x+2y)^2 = x^2+ pxy +4y^2
x^2 + 4xy + 4y^2 = x^2 + 4xy +4y^2
Then p = 4
If x^2+4y^2=40 ……………(i) and xy=6
If xy=6 Therefore, x=6/y
Put x=6/y in (i)
(6/y)^2+4y^2=40
36/y^2+4y^2=40
(36+4y^4)/y^2=40
36+4y^4=40y^2 …………..(ii)
Let y^2=z
therefore, equation (ii) becomes
36+4z^2=40z ………. (iii)
Divide (iii) by 4 it becomes
9+z^2=10z
z^2–10z+9=0……………(iv)
z^2-z-9z+9=0
z(z-1)-9(z-1)=0
(z-1)(z-9)=0
Hence, Z=1 or 9
Taking Z=1, We have
y^2=1
y=1
Taking Z=9, we have
y^2=9
y=3
Putting y=1 in equation (i), we have
x^2+4(1)^2=40
x^2+4=40
x^2=36
x=6
Therefore, x+2y= 6+2(1)=6+2=8
Putting y=3 in equation (i) we have,
x^2+4(3)^2=40
x^2+4(9)=40
x^2=40–36
x^2=4
x=2
Therefore, x+2y= 2+2(3)=2+6=8