Putting the given values (2p-1 , 1) in the given equation => 9(2p-1) +12 = 10(1) => 18p – 9 +12 = 10 => 18p – 3 = 10 => 18p = 10 +3 => 18p = 13 => p = 13/18 ❥ÏtzÇöttöñÇäñdy65 Reply
Answer: 2 Step-by-step explanation: 9y+12=10x here (x y)=(2p-1,p) put the value 9(p)+12=10(2p-1) 9p+12=20p-10 12+10=20p-9p 22=11p p=22/11 p=2 Reply
Putting the given values (2p-1 , 1) in the given equation
=> 9(2p-1) +12 = 10(1)
=> 18p – 9 +12 = 10
=> 18p – 3 = 10
=> 18p = 10 +3
=> 18p = 13
=> p = 13/18
❥ÏtzÇöttöñÇäñdy65
Answer:
2
Step-by-step explanation:
9y+12=10x
here (x y)=(2p-1,p)
put the value
9(p)+12=10(2p-1)
9p+12=20p-10
12+10=20p-9p
22=11p
p=22/11
p=2