If 2 is added to the numeratorof a fraction, it reduces to 1/2 andif 1 is subtracted from the denominator, it reduces to 1/3. Find the fraction. About the author Elliana
Let the required fraction be x/y . Then, we have: x+2/y = 1/2 ⇒ 2(x + 2) = y ⇒ 2x + 4 = y ⇒2x – y = -4 ……(i) Again, x/y−1 = 1/3 ⇒3x = 1(y – 1) ⇒3x – y = -1 ……(ii) On subtracting (i) from (ii), we get: x = (-1 + 4) = 3 On substituting x = 3 in (i), we get: 2 × 3 – y = -4 ⇒ 6 – y = -4 ⇒ y = (6 + 4) = 10 ∴ x = 3 and y = 10 Hence, the required fraction is 3/10 Reply
Let the required fraction be x/y .
Then, we have: x+2/y = 1/2
⇒ 2(x + 2) = y
⇒ 2x + 4 = y
⇒2x – y = -4 ……(i)
Again, x/y−1 = 1/3
⇒3x = 1(y – 1)
⇒3x – y = -1 ……(ii)
On subtracting (i) from (ii),
we get: x = (-1 + 4) = 3
On substituting x = 3 in (i),
we get: 2 × 3 – y = -4
⇒ 6 – y = -4
⇒ y = (6 + 4) = 10
∴ x = 3 and y = 10
Hence, the required fraction is 3/10