If -1 is root of equation x2 + px +12=0, find the value of p.

Question

If -1 is root of equation x2 +  px +12=0, find the value of  p.​

Luna · Answer

Answer: p = 13    Solution is in this picture!!!  I hope it will help you!!!☺️

Quinn · Answer

{x}^{2}  + px + 12 = 0    since  :  - 1  : is  : a  : root  : of  : the  : equation  :      { (- 1)}^{2}  + p( - 1) + 12 = 0    1 - p + 12 = 0     p = 13     t    h    e    r    e         y    o    u         g    o         :    )

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Maya

three coins are tossed write the sample space and number of sample point

in the diagram, AB is the chord of the circle
with centre o. OC is the perpendicular to AB
IF AB – 6cm. Find BC

2 thoughts on “If -1 is root of equation x2 + px +12=0, find the value of p.”

If -1 is root of equation x2 + px +12=0, find the value of p.​

Maya

three coins are tossed write the sample space and number of sample point​

in the diagram, AB is the chord of the circlewith centre o. OC is the perpendicular to ABIF AB – 6cm. Find BC

2 thoughts on “If -1 is root of equation x2 + px +12=0, find the value of p.​”