if (x-1)is a factor of p(x) =kx square -√2x+1 then find the value of k​

2 thoughts on “if (x-1)is a factor of p(x) =kx square -√2x+1 then find the value of k​”

1. Answer:

   k = √2 – 1

   Step-by-step explanation:

   If (x-1) is a factor of p(x) then, p(1) = 0.

   So, k×(1)² – √2×1 + 1 = 0

   => k – √2 + 1 = 0

   => k = √2 – 1

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2. Answer:

   31,64 31,61,49 86944 558 64)5664. 6494

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