Answer: we have area formula of triangle, Δ = 1/2 [ x₁ ( y₂ – y₃ ) + x₂ ( y₃ – y₁ ) + x₃ ( y₁ – y₂ ) ] (x₁ , y₁) = ( 0 , 0 ) , ( x₂ , y₂ ) = ( 2 , 0 ) , ( x₃ , y₃ ) = ( 0 , 3 ) Δ = 1/2 [ 0 ( 0 – 3 ) + 2 ( 3 – 0 ) + 0 ( 0 – 3 ) Δ = 1/2 * 6 Δ = 3 unit² (Ans.) Reply

Answer: Example: What is the area of the ∆ABC whose vertices are A(1, 2), B(4, 2) and C(3, 5)? A = (1/2) [-3 + 12]= 9/2 square units. Therefore, the area of a triangle ABC is 9/2 square units Reply

Answer:we have area formula of triangle,Δ = 1/2 [ x₁ ( y₂ – y₃ ) + x₂ ( y₃ – y₁ ) + x₃ ( y₁ – y₂ ) ](x₁ , y₁) = ( 0 , 0 ) , ( x₂ , y₂ ) = ( 2 , 0 ) , ( x₃ , y₃ ) = ( 0 , 3 )Δ = 1/2 [ 0 ( 0 – 3 ) + 2 ( 3 – 0 ) + 0 ( 0 – 3 )Δ = 1/2 * 6Δ = 3 unit² (Ans.)Answer:Example: What is the area of the ∆ABC whose vertices are A(1, 2), B(4, 2) and C(3, 5)? A = (1/2) [-3 + 12]= 9/2 square units. Therefore, the area of a triangle ABC is 9/2 square units