if (0,0),(2,0),(0,3),are vertices of a triangle then find its area​

2 thoughts on “if (0,0),(2,0),(0,3),are vertices of a triangle then find its area​”

1. Answer:

   we have area formula of triangle,

   Δ = 1/2 [ x₁ ( y₂ – y₃ ) + x₂ ( y₃ – y₁ ) + x₃ ( y₁ – y₂ ) ]

   (x₁ , y₁) = ( 0 , 0 ) , ( x₂ , y₂ ) = ( 2 , 0 ) , ( x₃ , y₃ ) = ( 0 , 3 )

   Δ = 1/2 [ 0 ( 0 – 3 ) + 2 ( 3 – 0 ) + 0 ( 0 – 3 )

   Δ = 1/2 * 6

   Δ = 3 unit² (Ans.)

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2. Answer:

   Example: What is the area of the ∆ABC whose vertices are A(1, 2), B(4, 2) and C(3, 5)? A = (1/2) [-3 + 12]= 9/2 square units. Therefore, the area of a triangle ABC is 9/2 square units

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