How much pressure is exerted on the head of a nail when it is struck with a force of 50 N and area of contact is 0.00002 m 2?

2 thoughts on “How much pressure is exerted on the head of a nail when it is struck with a force of 50 N and area of contact is 0.00002 m 2?”

1. Given:–

   • Force ,F = 50 N

   • Area on which force act ,A = 0.00002 m²

   To Find:–

   • Pressure is exerted on the head of nail,P

   Solution:–

   We have to calculate the pressure exerted on the head of a nail when force of 50 N is applied on nail and the area of contact with nail is 0.00002 m².

   As we know that Pressure is calculated by the force acting per unit area.

   • P = F/A

   where,

   • P denote pressure
   • A denote area on which the force acted
   • F denote force

   Substitute the value we get

   [tex]:\implies[/tex] P = 50/0.00002

   [tex]:\implies[/tex] P = 50×100000/2

   [tex]:\implies[/tex] P = 25×100000

   [tex]:\implies[/tex] P = 2500000 Pa

   • Hence, the pressure exerted on the tip of the nail is 2500000 Pascal or 2500 KiloPascal.

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2. Answer:

   Given :–

   pressure is exerted on the head of a nail when it is struck with a force of 50 N and area of contact is 0.00002 m²

   To Find :–

   Pressure

   Solution :–

   We know that

   P = F/A

   P = pressure

   f = force

   a = acceleration

   P = 50/0.00002

   P = 2500000 Pa

   [tex] \\ [/tex]

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