HCF is always (a) multiple of LCM (b)factor of LCM (c)divisible by LCM (d) a and c both
2 thoughts on “HCF is always (a) multiple of LCM (b)factor of LCM (c)divisible by LCM (d) a and c both”
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Answer:
b
Step-by-step explanation:
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Answer:
(b) i
Step-by-step explanation:
(b)factor of LCM is correct answer