1 thought on “Glen rolls a fair dice and flips a fair coin.<br />
What is the probability of obtaining a number less than 2 and a head?”
Answer:
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So, for the odd number, we get 3/6 since we have 1,2,3,4,5,6 as possible outcomes and only 1,3, and 5 are odd numbers. Then, since those two events are independent (meaning the outcome of one of the events doesn’t affect the outcome of the other one), we can multiply the probability of both of them to get the intersection.
The probability of getting a tail (assuming it’s an unbiased coin) is 1/2. Therefore, the probability of both events ocurring would be: P(odd number & tail) = P(odd number) * P(tail) = 3/6 * 1/2 = 3/12 = 1/4. where P:= probability
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EXTRAINFORMATION:
(3/6)(1/2) = 1/4
(3/6)(1/2) = 1/4“even” or “odd” treats a die as a coin with “heads” or “tails”.
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You have a 3 in 6 chance to get an odd number, and a 1 in 2 chance to get a heads. If you multiply these together, you have 3 total Odds\Heads combos out of 12 total combos, so your chances are 1 in 4.
Answer:
______________________
So, for the odd number, we get 3/6 since we have 1,2,3,4,5,6 as possible outcomes and only 1,3, and 5 are odd numbers. Then, since those two events are independent (meaning the outcome of one of the events doesn’t affect the outcome of the other one), we can multiply the probability of both of them to get the intersection.
The probability of getting a tail (assuming it’s an unbiased coin) is 1/2. Therefore, the probability of both events ocurring would be: P(odd number & tail) = P(odd number) * P(tail) = 3/6 * 1/2 = 3/12 = 1/4. where P:= probability
____________________
EXTRA INFORMATION :
(3/6)(1/2) = 1/4
(3/6)(1/2) = 1/4“even” or “odd” treats a die as a coin with “heads” or “tails”.
_____________________
You have a 3 in 6 chance to get an odd number, and a 1 in 2 chance to get a heads. If you multiply these together, you have 3 total Odds\Heads combos out of 12 total combos, so your chances are 1 in 4.