Given that kx + 6y = 1 and 2x + 3y = 1, what should be the value of k so that there will be no solution?

Given that kx + 6y = 1 and 2x + 3y = 1, what should be the value of k so that there will be no solution?

About the author
Isabella

2 thoughts on “Given that kx + 6y = 1 and 2x + 3y = 1, what should be the value of k so that there will be no solution?”

  1. Step-by-step explanation:

    The system of these two equations has no solution means the lines in the plane corresponding to the equations are distinct and parallel. This happens iff their slopes are equal but y-intercepts are different.

    Note that the equation y=mx+c represents a line with slope m and y-intercept c.

    Hence, in this problem, the required conditions are −K2=−31 and 52≠1

    Hence we get K= 6 as the required condition.

    Reply

Leave a Reply to Remi Cancel reply