From the sum of 2×2 + 3xy – 5 and 7 + 2xy – x

2

subtract 3xy + x2 – 2.​

1 thought on “From the sum of 2×2 + 3xy – 5 and 7 + 2xy – x<br /><br />2<br /><br />subtract 3xy + x2 – 2.​”

1. Answer:

   Given to find sum of [tex]2x^2+3xy-5[/tex] and [tex]7+2xy-x^2[/tex]

   [tex](2x^2+3xy-5)+(7+2xy-x^2)= (2x^2-x^2)+(3xy+2xy)+(-5+7)[/tex]

   [tex]=x^2+5xy+2[/tex]

   Now we should find the difference between [tex]x^2+5xy+2[/tex] and [tex]3xy + x^2 -2[/tex]

   [tex](x^2+5xy+2)-(3xy+x^2-2)= (x^2-x^2)+(5xy-3xy)+[2-(-2)][/tex]

   [tex]= 0 +2xy+ (2+2)[/tex]

   [tex]=2xy+4[/tex]

   Hope it helps you^_^

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