four numbers are in Ap the sum of externs is 10 and the product of the means is 24 find the namber About the author Eliza

Answer: first term = 5 common difference = 1 Explanation: let the numbers in the AP as a-3d, a-d, a+d, a+3d According to the question, (a-3d)+(a+3d) = 10 →2a = 10 →a= 10/2 = 5 →(1) and (a-d)(a+d) = 24 →a²-d² = 24 from (1) we get 5²-d² = 24 →d² = 25-24 →d = √1 = 1 Step-by-step explanation: Reply

Answer:first term = 5

common difference = 1

Explanation:

let the numbers in the AP as a-3d, a-d, a+d, a+3d

According to the question,

(a-3d)+(a+3d) = 10

→2a = 10

→a= 10/2 = 5 →(1)

and (a-d)(a+d) = 24

→a²-d² = 24

from (1) we get 5²-d² = 24

→d² = 25-24

→d = √1 = 1

Step-by-step explanation: