four numbers are in Ap the sum of externs is 10 and the product of the means is 24 find the namber​

1 thought on “four numbers are in Ap the sum of externs is 10 and the product of the means is 24 find the namber​”

1. Answer:

   first term = 5

   common difference = 1

   Explanation:

   let the numbers in the AP as a-3d, a-d, a+d, a+3d

   According to the question,

   (a-3d)+(a+3d) = 10

   →2a = 10

   →a= 10/2 = 5 →(1)

   and (a-d)(a+d) = 24

   →a²-d² = 24

   from (1) we get 5²-d² = 24

   →d² = 25-24

   →d = √1 = 1

   Step-by-step explanation:

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