for what value of k, 1/4 is a root of the quadratic equation kx2 – x + 1/8 = 0? About the author Amaya
Solution [tex] \sf \: x=2 \: one \: of \: the \: root \: of \: kx^2 −x+1/8=0[/tex] [tex] \sf \: f(2)=0[/tex] [tex] \sf \: f(x)=kx^2 −x+1/8[/tex] [tex] \sf=k(2)^2 −x×2+1/8=0[/tex] [tex] \sf \implies4k−28+8=0[/tex] [tex] \sf \implies4k=20[/tex] [tex] \sf \: ∴k=5[/tex] [tex]\fbox\red{hope its helpful dear❤}[/tex] Reply
In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity (which includes to begin moving from a state of rest), i.e., to accelerate. Reply
Solution
[tex] \sf \: x=2 \: one \: of \: the \: root \: of \: kx^2 −x+1/8=0[/tex]
[tex] \sf \: f(2)=0[/tex]
[tex] \sf \: f(x)=kx^2 −x+1/8[/tex]
[tex] \sf=k(2)^2 −x×2+1/8=0[/tex]
[tex] \sf \implies4k−28+8=0[/tex]
[tex] \sf \implies4k=20[/tex]
[tex] \sf \: ∴k=5[/tex]
[tex]\fbox\red{hope its helpful dear❤}[/tex]
In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity (which includes to begin moving from a state of rest), i.e., to accelerate.