For what value of k,

1
/4
is a root of the quadratic equation kx^2-x+
1/8= 0 ?​

2 thoughts on “For what value of k, <br /><br />1<br /> /4<br /> is a root of the quadratic equation kx^2-x+<br /> 1/8= 0 ?​”

1. Answer:

   x=1/4

   =kx²-x+1/8=0

   k(1/4)²-(1/4)+1/8=0

   1/16k-1/4+1/8=0

   k-4+2. =0

   16

   k-2 =0

   k=2

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2. Step-by-step explanation:

   GIVEN:-

   1/4 is a root of the quadratic equation kx^2 -x+1/8.

   TO FIND:-

   The value of k.

   UNDERSTANDING THE CONCEPT:-

   According to your question,

   1/2 is a root of quadratic equation.

   So, It must satisfy the quadratic equation.

   => kx^2 – x + 1/8 = 0

   REQUIRED ANSWER:-

   [tex]k( \dfrac{1}{4} ) {}^{2} – \dfrac{1}{4} + \dfrac{1}{8} = 0[/tex]

   [tex] \dfrac{k}{16} – \dfrac{1}{4} + \dfrac{1}{8} = 0[/tex]

   LCM = 16

   [tex] \dfrac{k – 4 + 2}{16} = 0[/tex]

   [tex]k – 2 = 0[/tex]

   => k = 2

   Therefore, Value of k is 2.

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