\begin{gathered}The \: \: mode \: \: is \: \: the \: \: value \\ that \: \: appears \: \: most \: \: frequently \\ i n \: \: a \: \: data \: \: set\\ \\ \therefore \: \: mode \: \: is \: \: 4 \: \: and \: \: 2\end{gathered}
\\ ————————————————– \\ \begin{gathered}The \: \: median \: \: is \: \: the \: \: central \\ number \: \: of \: \: a \: \: data \: \: set. \\ \\ ascending \: \: order \\1 = 1 < 2 = 2 = 2 < 3 = 3 < 4 = 4 = 4 < 5 = 5 < 6 = 6 < 8 \\ \\ \therefore \: \: median \: \:i s \: \: 4\end{gathered}
[tex]The \: \: mode \: \: is \: \: the \: \: value \\ that \: \: appears \: \: most \: \: frequently \\ i n \: \: a \: \: data \: \: set\\ \\ \therefore \: \: mode \: \: is \: \: 4 \: \: and \: \: 2[/tex]
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[tex]The \: \: median \: \: is \: \: the \: \: central \\ number \: \: of \: \: a \: \: data \: \: set. \\ \\ ascending \: \: order \\1 = 1 < 2 = 2 = 2 < 3 = 3 < 4 = 4 = 4 < 5 = 5 < 6 = 6 < 8 \\ \\ \therefore \: \: median \: \:i s \: \: 4[/tex]
Answer:
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Step-by-step explanation:
[tex]Mean= \frac{sum \: \: of \: \: observations}{no. \: \: of \: \: observations} \\ \\ Mean= \frac{5+3+4+1+6+2+2+4+3+2+1+5+4+6+8}{15} \\ \\ Mean= \frac{56}{15} \\ \\ Mean=3.733 \\ ————————————————– \\
\begin{gathered}The \: \: mode \: \: is \: \: the \: \: value \\ that \: \: appears \: \: most \: \: frequently \\ i n \: \: a \: \: data \: \: set\\ \\ \therefore \: \: mode \: \: is \: \: 4 \: \: and \: \: 2\end{gathered}
\\ ————————————————– \\ \begin{gathered}The \: \: median \: \: is \: \: the \: \: central \\ number \: \: of \: \: a \: \: data \: \: set. \\ \\ ascending \: \: order \\1 = 1 < 2 = 2 = 2 < 3 = 3 < 4 = 4 = 4 < 5 = 5 < 6 = 6 < 8 \\ \\ \therefore \: \: median \: \:i s \: \: 4\end{gathered}
[/tex]
Answer:
Hope it helps!! Mark this answer as brainliest if u found it useful and follow me for quick and accurate answers…
Step-by-step explanation:
[tex]{Mean = \frac{sum \: \: of \: \: observations}{no. \: \: of \: \:observations } } \\ \\ Mean = \frac{5 + 3 + 4 + 1 + 6+ 2 + 2 +4 + 3 + 2 + 1 + 5 + 4 + 6 + 8}{15} \\ \\ Mean = \frac{56}{15} \\ \\ Mean = 3 . 733 [/tex]
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[tex]The \: \: mode \: \: is \: \: the \: \: value \\ that \: \: appears \: \: most \: \: frequently \\ i n \: \: a \: \: data \: \: set\\ \\ \therefore \: \: mode \: \: is \: \: 4 \: \: and \: \: 2[/tex]
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[tex]The \: \: median \: \: is \: \: the \: \: central \\ number \: \: of \: \: a \: \: data \: \: set. \\ \\ ascending \: \: order \\1 = 1 < 2 = 2 = 2 < 3 = 3 < 4 = 4 = 4 < 5 = 5 < 6 = 6 < 8 \\ \\ \therefore \: \: median \: \:i s \: \: 4[/tex]