find TSA volume of a cylinder if radius is 3.5 cm and height is 25 CM(step by step explanation) About the author Josephine

The radius of the cylindrical bucket is r=3.5 cm. The height is h=12 cm. The total surface area of bucket is TSA=2\pi r(r+h) TSA=2πr(r+h) As top is open then area is A=2\pi rA=2πr The total surface area, if top of the bucket is open is given by SA=2\pi r(r+h)-2\pi rSA=2πr(r+h)−2πr Substitute the value in the formula, SA=2\times 3.14\times (3.5+12)-2\times 3.14\times 3.5SA=2×3.14×(3.5+12)−2×3.14×3.5 SA=2\times 3.14\times 15.5-2\times 3.14\times 3.5SA=2×3.14×15.5−2×3.14×3.5 SA=97.34-21.98SA=97.34−21.98 SA=75.36SA=75.36 Therefore, the total surface area,if top of the bucket is open is 75.36 square cm. Reply

The radius of the cylindrical bucket is r=3.5 cm.

The height is h=12 cm.

The total surface area of bucket is TSA=2\pi r(r+h)

TSA=2πr(r+h)

As top is open then area is A=2\pi rA=2πr

The total surface area, if top of the bucket is open is given by

SA=2\pi r(r+h)-2\pi rSA=2πr(r+h)−2πr

Substitute the value in the formula,

SA=2\times 3.14\times (3.5+12)-2\times 3.14\times 3.5SA=2×3.14×(3.5+12)−2×3.14×3.5

SA=2\times 3.14\times 15.5-2\times 3.14\times 3.5SA=2×3.14×15.5−2×3.14×3.5

SA=97.34-21.98SA=97.34−21.98

SA=75.36SA=75.36

Therefore, the total surface area,if top of the bucket is open is 75.36 square cm.