find the zeros of the quadratic polynomial 2x*2-7x-9 and also verify the relation between the zeros and the coefficient of the polynomial About the author Iris

Answer: x = 4.5 and x= -1 Step-by-step explanation: [tex]2x^{2} -7x-9=0[/tex] we know that for [tex]ax^{2}+bx+c=0[/tex] roots are: x=(-b±[tex]\sqrt{b^{2}-4ac }[/tex])/2a; so here a=2, b= -7, c= -9 x=(-(-7)±[tex]\sqrt{7^{2} -4*2*(-9)}[/tex])/2*2 x=(7±11)/4 x=4.5 or x= -1 so answer is x=4.5 or x= -1 Reply

Answer:## x = 4.5 and x= -1

Step-by-step explanation:[tex]2x^{2} -7x-9=0[/tex]

we know that for [tex]ax^{2}+bx+c=0[/tex]

roots are:

x=(-b±[tex]\sqrt{b^{2}-4ac }[/tex])/2a;

so here a=2, b= -7, c= -9

x=(-(-7)±[tex]\sqrt{7^{2} -4*2*(-9)}[/tex])/2*2

x=(7±11)/4

## x=4.5 or x= -1

so answer is x=4.5 or x= -1