find the zeros of the quadratic polynomial 2x*2-7x-9 and also verify the relation between the zeros and the coefficient of the polynomial About the author Iris
Answer: x = 4.5 and x= -1 Step-by-step explanation: [tex]2x^{2} -7x-9=0[/tex] we know that for [tex]ax^{2}+bx+c=0[/tex] roots are: x=(-b±[tex]\sqrt{b^{2}-4ac }[/tex])/2a; so here a=2, b= -7, c= -9 x=(-(-7)±[tex]\sqrt{7^{2} -4*2*(-9)}[/tex])/2*2 x=(7±11)/4 x=4.5 or x= -1 so answer is x=4.5 or x= -1 Reply
Answer:
x = 4.5 and x= -1
Step-by-step explanation:
[tex]2x^{2} -7x-9=0[/tex]
we know that for [tex]ax^{2}+bx+c=0[/tex]
roots are:
x=(-b±[tex]\sqrt{b^{2}-4ac }[/tex])/2a;
so here a=2, b= -7, c= -9
x=(-(-7)±[tex]\sqrt{7^{2} -4*2*(-9)}[/tex])/2*2
x=(7±11)/4
x=4.5 or x= -1
so answer is x=4.5 or x= -1