find the zeros of the polynomial x²-5x-24 and verify the relationship between the zeroes and coefficient​

2 thoughts on “find the zeros of the polynomial x²-5x-24 and verify the relationship between the zeroes and coefficient​”

1. Answer:ans -5;-40

   Step-by-step explanation:

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2. Answer:

   given, the polynomial,

   x2-5x-24

   = x2-(8-3)x-24

   = x2-8x+3x-24

   = x(x-8)+3( x-8)

   = (x-8)(x+3)

   now,for the zeores,

   (x-8)(x+3)=0

   = x-8= 0. or. x+3=0

   = x=8. or. x= -3

   now, the total of zeores = 8+(-3)

   = 8-3

   = 5

   = {coefficient of(-x)}/ (coefficient of x2)

   and, the multiplication of zeores= 8×(-3)

   = -24

   =constant term/ coefficient of x2)

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