find the zeros of the following quadratic polynomials and verify the relationship between the zeros and the coefficient.t²-15 About the author Liliana
Finding zeroes: t² – 15 = t²-(√15)² 0 = (t+√15)(t-√15) Therefore, t+√15= 0 t = -√15 t-√15 = 0 t = √15 Verification of the relationship: α + β = -b/a √15+(-√15) = -0/1 0 = 0 αβ = c/a (√15)(√15) = 15/1 15 = 15 Hence proved. Reply
Answer:
Therefore, the zeros of the quadratic polynomial are +√15=3.87 and −√15=−3.87.
Finding zeroes:
t² – 15 = t²-(√15)²
0 = (t+√15)(t-√15)
Therefore,
t+√15= 0
t = -√15
t-√15 = 0
t = √15
Verification of the relationship:
α + β = -b/a
√15+(-√15) = -0/1
0 = 0
αβ = c/a
(√15)(√15) = 15/1
15 = 15
Hence proved.