Find the zeroes of the polynomial f(x) = (√3x² – 8x + 4√3 and
verify the relationship between the zeroes and its
coeffic

2 thoughts on “Find the zeroes of the polynomial f(x) = (√3x² – 8x + 4√3 and<br />verify the relationship between the zeroes and its<br />coeffic”

1. Step-by-step explanation:

   √3x²-6x-2x+4√3=0

   √3x(x-2√3) -2(x-2√3)=0

   either (√3x-2) or (x-2√3) = 0

   (√3x-2)=0 (x-2√3) =0

   x=2/√3 or x= 2√3.

   VERIFICATION :-

   SUM OF ZEROES = -b/a = -(-8/√3)= 8/√3

   2/√3 + 2√3 = 2+√3(2√3)/√3 = 8/√3

   PRODUCT OF ZEROES = c/a = 4√3/√3 = 4

   2/√3*2√3 = 4

   hence verified ..

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2. Answer:

   f(x)=√3x^2 -8x+4√3=0

   √3x^2-6x-2x+4√3=0

   √3x(x-2√3) -2(x-2√3) =0

   (√3x-2) (x-2√3)=0

   x=2/√3,2√3

   Step-by-step explanation:

   Verification

   Sum of zeroes =-b/a

   2/√3+2√3

   =8/√3. (by taking LCM)

   Product of zeroes=c/a

   2/√3×2√3

   =4=4√3/√3=c/a

   H.V

   Reply