Answer: [tex]\frac{2200x}{21} cm^{3}[/tex] Step-by-step explanation: Volume of cone = [tex]\frac{1}{3}[/tex] π [tex]r^{2} h[/tex] Given : r = 10cm , let h = x cm ⇒ Volume of cone = [tex](\frac{1}{3})( \frac{22}{7}) (10^{2})(x)[/tex]= [tex]\frac{2200x}{21} cm^{3}[/tex] Hope it helps, Consider marking as the brainliest? Reply
Step-by-step explanation: Volume of cone= 3 1 πr 1 2 h 1 = 3 1 π( 2 r ) 2 × 2 h = 3 1 π( 2 10 ) 2 × 2 h = 6 25πh cm 3 Volume of frustum ABCD= 3 1 πh 2 (R 2 +r 2 +Rr) = 3 1 π× 2 h (10 2 +5 2 +10×5) = 6 175πh Required ratio= 6 175πh 6 25πh = 175 25 = 7 1 =1.7 Reply
Answer:
[tex]\frac{2200x}{21} cm^{3}[/tex]
Step-by-step explanation:
Volume of cone = [tex]\frac{1}{3}[/tex] π [tex]r^{2} h[/tex]
Given : r = 10cm , let h = x cm
⇒ Volume of cone = [tex](\frac{1}{3})( \frac{22}{7}) (10^{2})(x)[/tex]= [tex]\frac{2200x}{21} cm^{3}[/tex]
Hope it helps, Consider marking as the brainliest?
Step-by-step explanation:
Volume of cone=
3
1
πr
1
2
h
1
=
3
1
π(
2
r
)
2
×
2
h
=
3
1
π(
2
10
)
2
×
2
h
=
6
25πh
cm
3
Volume of frustum ABCD=
3
1
πh
2
(R
2
+r
2
+Rr)
=
3
1
π×
2
h
(10
2
+5
2
+10×5)
=
6
175πh
Required ratio=
6
175πh
6
25πh
=
175
25
=
7
1
=1.7