find the values of ‘a’ and ‘b’ if the pair of linear equations (a-4)x +2y+(2b+1)=0 and (a-1)d + 4y +(5b-1)=0 has infinite solutions About the author Liliana
Step-by-step explanation: 2x−(a−4)y=2b+1 4x−(a−1)y=5b−1 Considering 2x−(a−4)y=2b+1 Comparing with a 1 x+b 1 y=c 1 a 1 =2 b 1 =−(−a−4) and c 1 =2b+1 Now considering 4x−(a−1)y=5b−1 Comparing with a 2 x+b 2 y=c 2 a 2 =4 b 2 =−(a−1) and c 2 =5b−1 For infinite number of solutions , a 2 a 1 = b 2 b 1 = c 2 c 1 ∴ 4 2 = −(a−1) −(a−4) = 5b−1 2b+1 Considering a−1 a−4 = 2 1 ⇒2a−8=a−1 ⇒a=7 And now for b consider 5b−1 2b+1 = 2 1 ⇒4b+2=5b−1 ∴b=3 ∴ The given system of equation will have infinitely many solution if a=7 and b=3. Reply
Step-by-step explanation:
2x−(a−4)y=2b+1
4x−(a−1)y=5b−1
Considering 2x−(a−4)y=2b+1
Comparing with
a
1
x+b
1
y=c
1
a
1
=2
b
1
=−(−a−4)
and c
1
=2b+1
Now considering 4x−(a−1)y=5b−1
Comparing with
a
2
x+b
2
y=c
2
a
2
=4
b
2
=−(a−1)
and c
2
=5b−1
For infinite number of solutions ,
a
2
a
1
=
b
2
b
1
=
c
2
c
1
∴
4
2
=
−(a−1)
−(a−4)
=
5b−1
2b+1
Considering
a−1
a−4
=
2
1
⇒2a−8=a−1
⇒a=7
And now for b consider
5b−1
2b+1
=
2
1
⇒4b+2=5b−1
∴b=3
∴ The given system of equation will have infinitely many solution if a=7 and b=3.