find the value of the following expression when n= -2.a) 5n-2b) 5n²+5n-2c) n³+5n²+5n-2 About the author Adalyn
Answer: Here is your answer . Step-by-step explanation: [tex]a. \: 5( -2 ) – 2 \\ – 10 – 2 \\ = – 12 \\ \\ b. \: 5 {n}^{2} + 5n \: – 2 \\ 5 {( – 2)}^{2} + 5( – 2) – 2 \\ = 5(4) – 10 – 2 \\ = 20 – 12 \\ = 8 \\ \\ c. \: {n}^{3} + 5 {n}^{2} + 5n – 2 \\ { (- 2)}^{3} + 5 { (- 2)}^{2} + 5( – 2) – 2 \\ 8 + 5(4) – 10 – 2 \\ = 8 + 20 – 12 \\ = 28 – 12 \\ = 16[/tex] Hope it will help you. Reply
Answer: 5(-2)-2=-10-2=-12 5(-2)^2+5(-2)-2=5(4)-10-2=20-12=8 (-2)^3+5(-2)^2+5(-2)-2=-8+5(4)-10-2=-8+20-12=-12-12=-24 Reply
Answer:
Here is your answer .
Step-by-step explanation:
[tex]a. \: 5( -2 ) – 2 \\ – 10 – 2 \\ = – 12 \\ \\ b. \: 5 {n}^{2} + 5n \: – 2 \\ 5 {( – 2)}^{2} + 5( – 2) – 2 \\ = 5(4) – 10 – 2 \\ = 20 – 12 \\ = 8 \\ \\ c. \: {n}^{3} + 5 {n}^{2} + 5n – 2 \\ { (- 2)}^{3} + 5 { (- 2)}^{2} + 5( – 2) – 2 \\ 8 + 5(4) – 10 – 2 \\ = 8 + 20 – 12 \\ = 28 – 12 \\ = 16[/tex]
Hope it will help you.
Answer:
5(-2)-2=-10-2=-12
5(-2)^2+5(-2)-2=5(4)-10-2=20-12=8
(-2)^3+5(-2)^2+5(-2)-2=-8+5(4)-10-2=-8+20-12=-12-12=-24