Find the value of k, if the roots of the quadratic equation 2×2-6×+k=0 are real and equal About the author Autumn

Answer: 9 Step-by-step explanation: Comparing the question with ax²+by+c=0, we get, a=1; b=-6; c=k b2-4ac=0 (-6)²-4×1×k=0 36-4k=0 36=4k k=9 (4×9=36) Reply

Answer:9

Step-by-step explanation:Comparing the question with ax²+by+c=0, we get,

a=1; b=-6; c=k

b2-4ac=0

(-6)²-4×1×k=0

36-4k=0

36=4k

k=9 (4×9=36)

Answer:2

Step-by-step explanation:2×2-6×+k=0

4-6×+k=0

-2×+k=0

+k=0+2

k=2