Find the value of x for which 2x, (x+10) and (3x +2) are the three consecutive terms

of an AP​

Find the value of x for which 2x, (x+10) and (3x +2) are the three consecutive terms

of an AP​

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  1. Answer:

    x= 6

    Step-by-step explanation:

    If terms are in AP

    then a2-a1=a3-a2

    x+10 -2x = 3x+2-x-10

    -x +10 = 2x-8

    10+8= 2x+x

    3x = 18

    x = 6

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