Find the sum of first 40 terms of an ap whose 4 th term is 8 and 6th term is 24 About the author Margaret
ANSWER S40=5800 Step-by-step explanation: A4=A+3d=8 …(1) A6=A+5d=24 …(2) (1)–(2) A+3d=8 –A–5d=–24 _________ –2d=–16 d=8 A+3(8)=8 A=–16 S40=n/2(2a+(n–1)d) S40=20(–32+(39)8) S40=20(–32+312) S40=20(290) S40=5800 Reply
ANSWER
S40=5800
Step-by-step explanation:
A4=A+3d=8 …(1)
A6=A+5d=24 …(2)
(1)–(2)
A+3d=8
–A–5d=–24
_________
–2d=–16
d=8
A+3(8)=8
A=–16
S40=n/2(2a+(n–1)d)
S40=20(–32+(39)8)
S40=20(–32+312)
S40=20(290)
S40=5800