Find the standard equation of hyperbola with vertices (0,±5). and horizontal conjugate axis of length 6units

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Ava · Answer

Step-by-step explanation:   vertices are given. i. e, a=5 is given  length of conjugate axis = 2b =6   b=3  equation of hyperbola is,   y²/a² - x²/b²= 1   y²/25 - x²/9 = 1  Or, 9y² - 25x² =225

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