Find the standard equation of hyperbola with vertices (0,±5). and horizontal conjugate axis of length 6units

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Step-by-step explanation:vertices are given. i. e, a=5 is given

length of conjugate axis = 2b =6

b=3

equation of hyperbola is,

y²/a² – x²/b²= 1

y²/25 – x²/9 = 1

Or, 9y² – 25x² =225