Find the standard equation of hyperbola with vertices (0,±5). and horizontal conjugate axis of length 6units

Find the standard equation of hyperbola with vertices (0,±5). and horizontal conjugate axis of length 6units

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  1. Step-by-step explanation:

    vertices are given. i. e, a=5 is given

    length of conjugate axis = 2b =6

    b=3

    equation of hyperbola is,

    y²/a² – x²/b²= 1

    y²/25 – x²/9 = 1

    Or, 9y² – 25x² =225

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