Find the standard equation of hyperbola with vertices (0,±5). and horizontal conjugate axis of length 6units About the author Adalyn
Step-by-step explanation: vertices are given. i. e, a=5 is given length of conjugate axis = 2b =6 b=3 equation of hyperbola is, y²/a² – x²/b²= 1 y²/25 – x²/9 = 1 Or, 9y² – 25x² =225 Reply
Step-by-step explanation:
vertices are given. i. e, a=5 is given
length of conjugate axis = 2b =6
b=3
equation of hyperbola is,
y²/a² – x²/b²= 1
y²/25 – x²/9 = 1
Or, 9y² – 25x² =225