find the ratio in which y-axis divides the line segment joining the points (5,-6) and (-1,-4) . also find the point of trisection . About the author Katherine
Step-by-step explanation: Let the point be A(5,−6), B(−1,−4) and P(0,y) Point P is on y−axis,hence its x co-ordinate is 0.So, it is of the form P(0,y) Now, we have to find ratio. Let the ratio be k:1 Hence m 1 =k, m 2 =1, x 1 =5, y 1 =−6, x 2 =−1,y 2 =−4, x=0, y=0 Using sections formula x= m 1 +m 2 m 1 x 2 +m 2 x 1 ⇒0= k+1 −k+5 ∴k=5 Again y= m 1 +m 2 m 1 y 2 +m 2 y 1 = k+1 −4k−6 = 6 −20−6 for k=5 = 3 −13 Hence the coordiantes of point is P(0, 3 −13 ) Reply
Step-by-step explanation:
Let the point be A(5,−6), B(−1,−4) and P(0,y)
Point P is on y−axis,hence its x co-ordinate is 0.So, it is of the form P(0,y)
Now, we have to find ratio.
Let the ratio be k:1
Hence m
1
=k, m
2
=1, x
1
=5, y
1
=−6, x
2
=−1,y
2
=−4, x=0, y=0
Using sections formula x=
m
1
+m
2
m
1
x
2
+m
2
x
1
⇒0=
k+1
−k+5
∴k=5
Again y=
m
1
+m
2
m
1
y
2
+m
2
y
1
=
k+1
−4k−6
=
6
−20−6
for k=5
=
3
−13
Hence the coordiantes of point is P(0,
3
−13
)