1 thought on “find the ratio in which y-axis divides the line segment joining the points (5,-6) and (-1,-4) . also find the point of trisection”
Answer:
Given in right triangle PQR, QS = SR By Pythagoras theorem, we have PR2 = PQ2 + QR2 → (1) In right triangle PQS, we have PS2 = PQ2 + QS2 = PQ2 + (QR/2)2 [Since QS = SR = 1/2 (QR)] = PQ2 + (QR2/4) 4PS2 = 4PQ2 + QR2 ∴ QR2 = 4PS2 − 4PQ2 → (2) Put (2) in (1), we get PR2 = PQ2 + (4PS2 − 4PQ2) ∴ PR2 = 4PS2 − 3PQ2
Answer:
Given in right triangle PQR, QS = SR By Pythagoras theorem, we have PR2 = PQ2 + QR2 → (1) In right triangle PQS, we have PS2 = PQ2 + QS2 = PQ2 + (QR/2)2 [Since QS = SR = 1/2 (QR)] = PQ2 + (QR2/4) 4PS2 = 4PQ2 + QR2 ∴ QR2 = 4PS2 − 4PQ2 → (2) Put (2) in (1), we get PR2 = PQ2 + (4PS2 − 4PQ2) ∴ PR2 = 4PS2 − 3PQ2