Find the point on y axis which is equidistant from the points (3,2) and (4,6)

Find the point on y axis which is equidistant from the points (3,2) and (4,6)

2 thoughts on “Find the point on y axis which is equidistant from the points (3,2) and (4,6)”

  1. [tex] \huge \underline \bold \blue{AnSwEr ♡}[/tex]

    distances are equal from both the points so

    [tex]\sqrt{(x1-x)^{2}+(y1-y)^2 } = \sqrt{(x2-x)^{2}+(y2-y)^2 }(x1−x)2+(y1−y)2=(x2−x)2+(y2−y)2

    \sqrt{(3-x)^{2}+(2-y)^2 } = \sqrt{(4-x)^{2}+(6-y)^2 }(3−x)2+(2−y)2=(4−x)2+(6−y)2[/tex]

    as the point is in y-axis then x=0, so

    [tex]\sqrt{(3)^{2}+(2-y)^2 } = \sqrt{(4)^{2}+(6-y)^2 }(3)2+(2−y)2=(4)2+(6−y)2

    \ (3)^{2}+(2-y)^2 = \ (4)^{2}+(6-y)^2 (3)2+(2−y)2= (4)2+(6−y)2[/tex]

    After solving this we get:-

    y = 19.5

    • so the final coordinate is (0, 19.5).
  2. A primary care physician is a physician who provides both the first contact for a person with an undiagnosed health concern as well as continuing care of varied medical conditions, not limited by cause, organ system, or diagnosis. The term is primarily used in the United States

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