2 thoughts on “Find the perimeter of rectangle whose length and breadth are <br /><br />17 m and 8 m respectively.”
Given :
Length [tex] \leadsto [/tex] 17m
Breadth [tex] \leadsto [/tex] 8m
To find :
Perimeter of the Rectangle
Solution:
We have to find the Perimeter of the Rectangle by using the formula the both units are also same so we just have to apply formula then we will get the answer So, let’s solve!
Given :
To find :
Solution :
We have to find the Perimeter of the Rectangle by using the formula the both units are also same so we just have to apply formula then we will get the answer So, let’s solve!
[tex]\star\;\boxed{\sf{\purple{Perimeter_{\:(rectangle)} = 2 \times Length + Breadth}}}[/tex]
[tex] : \implies \: 2 \: \times \: \sf(17m \: + 8m) \\ \\ \\ : \implies \: 2 \: \times \: \sf \: 25m \\ \\ \\ \: \: \: \: \: \: \: : \implies \: { \underline{ \boxed{ \pink{ \mathfrak{50 \: m}}}}}[/tex]
•°• Hence, verified! that the Perimeter of the Rectangle is 50m
Diagram :
[Note :- Kindly see the diagram in the attachment]
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Step-by-step explanation:
primeter of retangle = 2( l + b )
= 2 ( 17 + 8 )
= 2( 25 )
= 50 sq.m