find the other two members of the py t h a g o r e a n t r i p l e t whose smallest number is 18​

1 thought on “find the other two members of the py t h a g o r e a n t r i p l e t whose smallest number is 18​”

1. Answer:

   required pythagorean triplet ( 18,80,82)

   Step-by-step explanation:

   [tex]pythgorean \: triplet \: (2m \: {m}^{2} – 1 \: {m}^{2} + 1)[/tex]

   smallest number = 2m= 18

   m= 9

   [tex] {m}^{2} – 1 = {9}^{2} – 1 = 80[/tex]

   [tex] {m}^{2} + 1 = {9}^{2} + 1 = 82[/tex]

   required pythagorean triplet ( 18,80,82)

   Reply