find the length of side of a square of side (2x-3) cm and whose perimeter is 68 cm?​

find the length of side of a square of side (2x-3) cm and whose perimeter is 68 cm?​

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  1. Answer:

    perimeter of square = 4a

    68 = 4(2x-3)

    68 = 8x-12

    56= 8x

    x= 56/8

    x= 7

    length = (2x-3)

    = (2*7-3)

    = (14-3)

    = 11 cm

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