Find the least number which when divided by 12,15,18 and 20 leaves a remainder 5 in each

Case.

Question

Find the least number which when divided by 12,15,18 and 20 leaves a remainder 5 in each    Case.​

Skylar · Answer

Answer:   First find the lcm of 12 15 18 and 20  which is 180     180 + 5 = 185     Step-by-step explanation:   Now check it with every number     Ak band nak band   chote thora sharp ban

Peyton

determine s={[a b c] , [b+1 c+1 a+1], [c-1 a-1 b-1]} is basis for r^3. if it is write in vector z=[1 2 3] as a linear

Tjree sides of a cuboid are ( x^2 +16), (x+4) and (x-4).Find the volume of the cuboid

1 thought on “Find the least number which when divided by 12,15,18 and 20 leaves a remainder 5 in each <br /><br /> Case.”

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Find the least number which when divided by 12,15,18 and 20 leaves a remainder 5 in each Case.​

Peyton

determine s={[a b c] , [b+1 c+1 a+1], [c-1 a-1 b-1]} is basis for r^3. if it is write in vector z=[1 2 3] as a linear​

Tjree sides of a cuboid are ( x^2 +16), (x+4) and (x-4).Find the volume of the cuboid​

1 thought on “Find the least number which when divided by 12,15,18 and 20 leaves a remainder 5 in each <br /><br /> Case.​”